如何将一个按 start 升序排列的数组进行合并，合并条件为 start 和 end 连续且 content 包含相同项？

[
    { "start": 1, "end": 2, "content": [ "a", "b", "e" ] },    //0
    { "start": 2, "end": 3, "content": [ "b", "c" ] },        //1
    { "start": 3, "end": 4, "content": [ "b", "d" ] },        //2
    { "start": 4, "end": 5, "content": [ "d" ] },            //3
    { "start": 7, "end": 8, "content": [ "b" ] },            //4
    { "start": 9, "end": 11, "content": [ "b", "c" ] }        //5
]

[
    { "start": 1, "end": 2, "content": [ "a", "e" ] },
    { "start": 1, "end": 4, "content": [ "b" ] },
    { "start": 2, "end": 3, "content": [ "c" ] },
    { "start": 3, "end": 5, "content": [ "d" ] },
    { "start": 7, "end": 8, "content": [ "b" ] },
    { "start": 9, "end": 11, "content": [ "b", "c" ] }
]

let arr = [
    { "start": 1, "end": 2, "content": [ "A", "B", "E" ] },
    { "start": 2, "end": 3, "content": [ "B", "C" ] },
    { "start": 3, "end": 4, "content": [ "B", "D" ] },
    { "start": 4, "end": 5, "content": [ "D" ] },
    { "start": 7, "end": 8, "content": [ "B" ] },
    { "start": 9, "end": 11, "content": [ "B", "C" ] }
]

let obj = {}
let list = arr.reduce((list, item, index, arr) => {
    item.content.forEach(citem => {
        let i = index
        let next, cindex
        while ((next = arr[i + 1]) && arr[i].end === next.start && (cindex = next.content.indexOf(citem)) >= 0) {
            i++
            next.content.splice(cindex, 1)
        }
        let end = arr[i].end
        let key = item.start + '-' + end
        if(!obj[key]){
            list.push(obj[key] = {
                start: item.start,
                end,
                content: [citem]
            })
        }else{
            obj[key].content.push(citem)
        }
    })
    return list
}, [])

console.log(list)