Golang：在特定时间实施类似Cron的任务 /执行任务

<code class="go">package main

import (
    "fmt"
    "time"
)

func main() {
    time.AfterFunc(3*time.Second, func() {
        fmt.Println("任务在3秒后执行")
    })

    time.Sleep(5 * time.Second) // 保持程序运行
}</code>

<code>任务在3秒后执行</code>

<code class="go">package main

import (
    "fmt"
    "time"
)

func main() {
    ticker := time.NewTicker(2 * time.Second)
    defer ticker.Stop()

    for range ticker.C {
        fmt.Println("任务执行于:", time.Now())
    }
}</code>

<code>任务执行于: 2025-02-07 12:00:00 +0000 UTC
任务执行于: 2025-02-07 12:00:02 +0000 UTC
任务执行于: 2025-02-07 12:00:04 +0000 UTC
...</code>

<code class="go">package main

import (
    "fmt"
    "time"

    "github.com/robfig/cron/v3"
)

func main() {
    c := cron.New()
    c.AddFunc("*/5 * * * * *", func() {
        fmt.Println("Cron任务执行于:", time.Now())
    })
    c.Start()
    select {} // 保持程序运行
}</code>

<code class="go">package main

import (
    "fmt"
    "time"

    "github.com/go-co-op/gocron"
)

func main() {
    s := gocron.NewScheduler(time.UTC)
    s.Every(10).Seconds().Do(func() {
        fmt.Println("计划任务执行于:", time.Now())
    })
    s.StartAsync()
    select {} // 保持程序运行
}</code>

<code>* * * * * /path/to/your-go-program</code>