如何获取指定DOM元素及其子元素相对于父元素的left和top属性值？

<div class="wrapper" id="wrapper">
    <div id="node-root">
        <div id="node-2">
            <div id="node-3"></div>
            <div id="node-3-1"></div>
            <div id="node-3-2"></div>
        </div>
        <div id="node-22">
            <div id="node-22-1"></div>
        </div>
        <div id="node-33">
            <div id="node-33-1"></div>
        </div>
    </div>
</div>

/**
 * 获取元素相对于文档的偏移量
 * @param {HTMLElement} ele DOM元素
 * @returns {{top: number, left: number}} 偏移量对象
 */
function getOffset(ele) {
  let offset = { top: 0, left: 0 };
  if (!ele || ele.nodeType !== 1) return offset;

  let offsetParent = ele.offsetParent;
  offset.top = ele.offsetTop;
  offset.left = ele.offsetLeft;

  while (offsetParent) {
    offset.top += offsetParent.offsetTop;
    offset.left += offsetParent.offsetLeft;
    offsetParent = offsetParent.offsetParent;
  }
  return offset;
}

/**
 * 获取元素相对于指定父元素的偏移量
 * @param {HTMLElement} ele DOM元素
 * @param {HTMLElement} parent 父元素
 * @returns {{top: number, left: number}} 偏移量对象
 */
function getOffsetInParent(ele, parent) {
  const elOffset = getOffset(ele);
  const parentOffset = getOffset(parent);
  return {
    top: elOffset.top - parentOffset.top,
    left: elOffset.left - parentOffset.left,
  };
}

// 示例调用: 获取'node-22-1'相对于'wrapper'的偏移量
const node221Offset = getOffsetInParent(document.getElementById('node-22-1'), document.getElementById('wrapper'));
console.log(node221Offset);