如何使用Comparator合并查找数组最大值和最小值的方法

private int findMin(int[] arr){
    int min = arr[0];
    for(int num : arr){
        if(num<min) {
            min = num;
        }
    }
    return min;
}

private int findMax(int[] arr){
    int max = arr[0];
    for(int num : arr){
        if(num>max){
            max = num;
        }
    }
    return max;
}

import java.util.Comparator;

public class ArrayUtils {

    public static int findExtreme(int[] arr, Comparator<Integer> comparator) {
        if (arr == null || arr.length == 0) {
            throw new IllegalArgumentException("Array cannot be null or empty");
        }
        int extreme = arr[0];
        for (int num : arr) {
            if (comparator.compare(num, extreme) > 0) {
                extreme = num;
            }
        }
        return extreme;
    }

    public static void main(String[] args) {
        int[] arr = {5, 2, 8, 1, 9, 4};

        // Find the maximum value
        int max = ArrayUtils.findExtreme(arr, Comparator.naturalOrder());
        System.out.println("Maximum value: " + max); // Output: Maximum value: 9

        // Find the minimum value
        int min = ArrayUtils.findExtreme(arr, Comparator.reverseOrder());
        System.out.println("Minimum value: " + min); // Output: Minimum value: 1
    }
}

int max = ArrayUtils.findExtreme(arr, Comparator.naturalOrder());

int min = ArrayUtils.findExtreme(arr, Comparator.reverseOrder());