解决 Spring JPA 外键约束创建错误：复合主键问题

package com.agilsistemas.construtordepedidos.model;

import java.io.Serializable;

import javax.persistence.Column;
import javax.persistence.Embeddable;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;

import lombok.AllArgsConstructor;
import lombok.EqualsAndHashCode;
import lombok.Getter;
import lombok.Setter;

@Embeddable
@Getter
@Setter
@EqualsAndHashCode
@AllArgsConstructor
public class IdClienteModel implements Serializable {

    @Column(name = "codigo")
    private int idCliente;

    @ManyToOne
    @JoinColumn(name = "empresa")
    private EmpresaModel idEmpresa;

}

package com.agilsistemas.construtordepedidos.model;

import java.io.Serializable;

import javax.persistence.Column;
import javax.persistence.EmbeddedId;
import javax.persistence.Entity;
import javax.persistence.Table;

import lombok.Getter;
import lombok.NoArgsConstructor;
import lombok.Setter;

@Entity
@Getter
@Setter
@NoArgsConstructor
@Table(name = "tbcadastro")
public class ClienteModel implements Serializable {

    @EmbeddedId
    private IdClienteModel idCliente; //using the object as the ID

    @Column(name = "razao")
    String razaoSocial;

    @Column(name = "logradouro")
    String rua;

    @Column(name = "numero")
    String numero;

    @Column(name = "bairro")
    String bairro;

    @Column(name = "complemento")
    String complemento;

    @Column(name = "cidade")
    String cidade;

    @Column(name = "fixo")
    String telefoneFixo;

    @Column(name = "celular")
    String celular;

    @Column(name = "cliente")
    String cliente;

}

@OneToOne
@JoinColumns({
        @JoinColumn(name = "fk_cliente", referencedColumnName = "codigo", insertable = false, updatable = false),
        @JoinColumn(name = "fk_empresa", referencedColumnName = "empresa", insertable = false, updatable = false) })
ClienteModel fkCliente;