PHP命令怎么调用Python脚本_PHP执行Python脚本与参数传递方法

$pythonScript = '/path/to/your/script.py';
$inputData = 'hello';
$command = "python3 $pythonScript " . escapeshellarg($inputData);
exec($command, $output, $status);

if ($status === 0) {
    echo "执行成功：\n";
    print_r($output); // 输出Python脚本的打印内容
} else {
    echo "执行失败，状态码：$status";
}

$command = "python3 /path/to/script.py arg1 arg2";
$result = shell_exec($command);
echo "<pre class="brush:php;toolbar:false;">$result

$arg1 = 'value1';
$arg2 = 'value2';
$command = "python3 script.py " . escapeshellarg($arg1) . " " . escapeshellarg($arg2);
$output = shell_exec($command);

import sys

if len(sys.argv) > 1:
    arg1 = sys.argv[1]
    arg2 = sys.argv[2]
    print(f"Received: {arg1}, {arg2}")
else:
    print("No arguments received")

$data = ['name' => '张三', 'age' => 25];
$jsonData = json_encode($data);
$command = "python3 receive_json.py " . escapeshellarg($jsonData);
$result = shell_exec($command);

import sys
import json

if len(sys.argv) > 1:
    data = json.loads(sys.argv[1])
    print(f"姓名: {data['name']}, 年龄: {data['age']}")