PHP语句日期比较有关问题

PHP语句日期比较问题
如何在提交页面的时候比较本页面表单中两个日期startdate与enddate的大小，并做出判断。
有没有不管date是什么类型都能转换为可以比较大小的类型的日期函数？
用php语句写，本人不会js跟ajax，谢谢了！

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PHP code

<?phpfunction getTime($date){$mon = array('Jan' => 1,'Feb' =&gt; 2,'Mar' =&gt; 3,'Apr' =&gt; 4,'May' =&gt; 5,'June'=&gt; 6,'July'=&gt; 7,'Aug' =&gt; 8,'Sept'=&gt; 9,'Oct' =&gt; 10,'Nov' =&gt; 11,'Dec' =&gt; 12);$m = substr($date, 0, strpos($date, '/'));$good = str_replace($m, $mon[$m], $date);// 返回整形的时间戳return strtotime($good);}$date1 = "Apr/13/2012";$date2 = "Apr/6/2012";// 4月13号比4月16号大，结果为truevar_dump( getTime($date1) &gt; getTime($date2) );<br><font color="#e78608">------解决方案--------------------</font><br>

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C/C++ code

[User:liangdong Time:13:54:44 Path:~/php]$ php date.php 2012/7/2[User:liangdong Time:13:54:46 Path:~/php]$ cat date.php <?phpfunction str_to_time($str_date) {        $mon_name = array(                                "Jan", "Feb", "Mar",                                "Apr", "May", "June",                                "July", "Aug", "Sept",                                "Oct", "Nov", "Dec"                        );        $mon_index = range(1, 12);        $str_date = str_replace($mon_name, $mon_index, $str_date);        return $str_date;}echo str_to_time("2012/July/2");?><br><font color="#e78608">------解决方案--------------------</font><br>

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PHP code

cat: cat: No such file or directory<?phpfunction str_to_time($str_date) {        $mon_name = array(                                "Jan", "Feb", "Mar",                                "Apr", "May", "June",                                "July", "Aug", "Sept",                                "Oct", "Nov", "Dec"                        );        $mon_index = range(1, 12);        $str_date = str_replace($mon_name, $mon_index, $str_date);        return @strtotime($str_date);}echo str_to_time("2012/July/2");?><div class="clear"></div>

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