PHP中遇到AJAX的问题
<?php<br />
header("Content-Type:html/text;Charset=utf-8");<br />
$name = $_POST['name'];<br />
$email = $_POST['email'];<br />
$comment = $_POST['comment'];<br />
$fh = @fopen("14-6.txt","ab");<br />
fwrite($fh,"姓名:".$name,strlen($name));<br />
fwrite($fh,"email:".$email,strlen($email));<br />
fwrite($fh,"评论:".$comment,strlen($comment));<br />
fclose($fh);<br />
echo 1;<br />
?>function $(id){<br />
return document.getElementById(id);<br />
}<br />
function addcomment(){<br />
var url = "14-6.php";<br />
var status = document.getElementById("divmsg");<br />
status.value="正在提交》》》";<br />
var param = "name="+$("name").value+"email="+$("email").value+"comment="+$("comment").value;<br />
xmlhttp_request.onreadystatechange = function(){<br />
if(xmlhttp_request.readyState==4 && xmlhttp_request.status == 200){//相应完全显示信息<br />
alert (xmlhttp_request.responseText);<br />
if(xmlhttp_request.responseText == "1"){<br />
status.value = "发表成功!!";<br />
$("name").value="";<br />
$("email").value="";<br />
$("comment").value="";<br />
}else{<br />
status.value = "发表失败!请重新发表!";<br />
}<br />
} <br />
}<br />
xmlhttp_request.open("POST",url,true);<br />
xmlhttp_request.setRequestHeader("Content-Type","application/x-www-form-urlencoded");//设置头信息<br />
xmlhttp_request.send(param);<br />
}
PHP怎么学习?PHP怎么入门?PHP在哪学?PHP怎么学才快?不用担心,这里为大家提供了PHP速学教程(入门到精通),有需要的小伙伴保存下载就能学习啦!
Copyright 2014-2025 https://www.php.cn/ All Rights Reserved | php.cn | 湘ICP备2023035733号