
您可以借助 MySQL 的 CHAR_LENGTH() 函数按字符长度排序。该函数返回字符数,即以下字符串的 4 个 -
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要按字符长度对字符串进行排序,语法如下 -
select *from yourTableName order by CHAR_LENGTH(yourColumnName);
为了理解上面的概念,让我们首先创建一个表。以下是创建表的查询 -
mysql> create table OrderByCharacterLength −> ( −> BookName varchar(200) −> ); Query OK, 0 rows affected (1.97 sec)
借助insert命令在表中插入一些记录。查询如下 -
mysql> insert into OrderByCharacterLength values('Let us C');
Query OK, 1 row affected (0.31 sec)
mysql> insert into OrderByCharacterLength values('Introduction to C');
Query OK, 1 row affected (0.20 sec)
mysql> insert into OrderByCharacterLength values('Data Structure And Algorithm in Java ');
Query OK, 1 row affected (0.13 sec)
mysql> insert into OrderByCharacterLength values('C in Depth');
Query OK, 1 row affected (0.17 sec)
mysql> insert into OrderByCharacterLength values('Java Projects');
Query OK, 1 row affected (0.23 sec)让我们按上表中插入的顺序显示所有记录。查询如下 -
mysql> select *from OrderByCharacterLength;
以下是输出 -
+---------------------------------------+ | BookName | +---------------------------------------+ | Let us C | | Introduction to C | | Data Structure And Algorithm in Java | | C in Depth | | Java Projects | +---------------------------------------+ 5 rows in set (0.00 sec)
这里是显示按照字符长度排列的所有记录的查询。如果列值具有最小长度,那么它将获得更高的优先级并首先显示。
查询如下 -
mysql> select *from OrderByCharacterLength order by CHAR_LENGTH(BookName);
以下是输出 -
+---------------------------------------+ | BookName | +---------------------------------------+ | Let us C | | C in Depth | | Java Projects | | Introduction to C | | Data Structure And Algorithm in Java | +---------------------------------------+ 5 rows in set (0.00 sec)
以上就是在 mYsql 中按字符长度对字符串进行排序?的详细内容,更多请关注php中文网其它相关文章!
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