我有两个不同的数组：
1
747accomodation: [
{
id: 1,
name: "Senator Hotel Fnideq",
address: "Route de Ceuta, 93100 Fnidek, Morocco",
checkin: "September 1",
fullCheckinDate: "2021-09-01",
checkout: "September 3",
fullCheckoutDate: "2021-09-03",
nights: 2,
mealplan: "Breakfast,Lunch"
},
{
id: 2,
name: "Kabek Morocco Hotel",
address: "Omis Juy, 93100 Kabek, Morocco",
checkin: "September 3",
fullCheckinDate: "2021-09-03",
checkout: "September 5",
fullCheckoutDate: "2021-09-05",
nights: 2,
mealplan: "Breakfast,Lunch"
}
]
experiences: [
{
id: 1,
fullDate: "2021-09-01",
title: "Arrival",
itinerary: // []
},
{
id: 2,
fullDate: "2021-09-02",
title: "Sightseeing",
itinerary: // []
}
]
我想找到一种方法将住宿和体验之间相同的日期组合成一个对象。
myTrips: [
{
accomodation: {
id: 1,
name: "Senator Hotel Fnideq",
address: "Route de Ceuta, 93100 Fnidek, Morocco",
checkin: "September 1",
fullCheckinDate: "2021-09-01",
checkout: "September 3",
fullCheckoutDate: "2021-09-03",
nights: 2,
mealplan: "Breakfast,Lunch"
},
experiences: {
id: 1,
fullDate: "2021-09-01",
title: "Arrival",
itinerary: // []
}
},
//... 另一个对象
]
我正在使用dayjs来处理日期。我该如何处理这个问题？
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const accomodation = [ { id: 1, name: "Senator Hotel Fnideq", address: "Route de Ceuta, 93100 Fnidek, Morocco", checkin: "September 1", fullCheckinDate: "2021-09-01", checkout: "September 3", fullCheckoutDate: "2021-09-03", nights: 2, mealplan: "Breakfast,Lunch" }, { id: 2, name: "Kabek Morocco Hotel", address: "Omis Juy, 93100 Kabek, Morocco", checkin: "September 3", fullCheckinDate: "2021-09-03", checkout: "September 5", fullCheckoutDate: "2021-09-05", nights: 2, mealplan: "Breakfast,Lunch" } ]; const experiences = [ { id: 1, fullDate: "2021-09-01", title: "Arrival", itinerary: [] }, { id: 2, fullDate: "2021-09-02", title: "Sightseeing", itinerary: [] } ]; const myTrips = []; accomodation.map(acc => { const experience = experiences.filter(exp => { const date = new Date(exp.fullDate); return date >= new Date(acc.fullCheckinDate) && date <= new Date(acc.fullCheckoutDate); }); myTrips.push({accomodation: acc, experience}); }); console.log(myTrips);