根据条件对数组进行计数：分步指南-PHP中文网问答

我有一个带有接口的主机列表。该代码必须计算每个主机的重复接口。最后，代码还必须为每个主机显示重复的接口 X 次。

我问这个问题是因为我想发送 X 主机有一个或多个失败接口发生故障的警报。

$data = array(
    array("192.168.0.1","eth1"),
    array("192.168.0.2","eth2"),
    array("192.168.0.3","eth3"),
    array("192.168.0.1","eth1"),
    array("192.168.0.4","eth1"),
    array("192.168.0.2","eth5")
);

我在这里遵循了其他示例，但大多数都是简单数组，或者如果是多维示例，则示例不相似。

我已经尝试过了...

<?php
$data = array(
    array("192.168.0.1","eth1"),
    array("192.168.0.2","eth2"),
    array("192.168.0.3","eth3"),
    array("192.168.0.1","eth1"),
    array("192.168.0.4","eth1"),
    array("192.168.0.2","eth5")
);


$counter_data = count($data);

$duplicated_host = array_filter(array_count_values(array_column($data, 0)), function($v) { return $v > 1; });
print_r($duplicated_host);
print ("<br>");

$duplicated_host_keys = (array_keys($duplicated_host));

for ($row_num = 0; $row_num < $counter_data; $row_num++)
{
    $host = $data[$row_num][0];
    $interface = $data[$row_num][1];
    if (in_array($host,$duplicated_host_keys))
    {
        print($host . " " . $interface . "<br>");
    }
    
}

上面的代码是错误的，有些工作，但它不是我所期望的...... 有没有简单的方法可以做到这一点？

最后的输出应如下所示：

Host 192.168.0.1 has eth1 repeated 2 times. --> For current data only
Host 192.168.0.1 has eth9 repeated 5 times.
Host 192.168.0.4 has eth1 repeated 9 times.

<?php $input = array( array("192.168.0.1","eth1"), array("192.168.0.2","eth2"), array("192.168.0.3","eth3"), array("192.168.0.1","eth1"), array("192.168.0.4","eth1"), array("192.168.0.2","eth5"), ); $output = []; array_walk($input, function($entry) use (&$output) { [$host, $interface] = $entry; if (isset($host, $output) && isset($interface, $output[$host])) { $output[$host][$interface]++; } else { $output[$host][$interface] = 1; } }); print_r($output);

Array ( [192.168.0.1] => Array ( [eth1] => 2 ) [192.168.0.2] => Array ( [eth2] => 1 [eth5] => 1 ) [192.168.0.3] => Array ( [eth3] => 1 ) [192.168.0.4] => Array ( [eth1] => 1 ) )

<?php $data = array( array("192.168.0.1","eth1"), array("192.168.0.2","eth2"), array("192.168.0.3","eth3"), array("192.168.0.1","eth1"), array("192.168.0.4","eth1"), array("192.168.0.2","eth5") ); $result = []; foreach ($data as $arr) { [ $host, $nic ] = $arr; if (!isset($result[$host])) { $result[$host] = []; } if (!isset($result[$host][$nic])) { $result[$host][$nic] = 0; } $result[$host][$nic]++; } foreach ($result as $host => $nics) { foreach ($nics as $nic => $count) { echo "${host} has his '${nic}' interface fail ${count} time(s)" . PHP_EOL; } }

192.168.0.1 has his 'eth1' interface fail 2 time(s) 192.168.0.2 has his 'eth2' interface fail 1 time(s) 192.168.0.2 has his 'eth5' interface fail 1 time(s) 192.168.0.3 has his 'eth3' interface fail 1 time(s) 192.168.0.4 has his 'eth1' interface fail 1 time(s)

在线试用！