可以使用array-filter函数来解决。即

$a1 = [
    ['id' => 1, 'status', 'active'], 
    ['id' => 2, 'status', 'in-active']
];

$search = 2;

print_r(array_filter($a1, function ($object) use ($search) {
    return $object['id'] == $search;
}));

它将从与搜索 id 匹配的数组中返回整个数组。

你也可以为此编写一个函数

function search($data, $searchValue, $searchField, $returnField) {

    $filter = array_filter($data, function ($object) use ($searchValue, $searchField) {
      return $object[$searchField] == $searchValue;
    });

   return count($filter) > 0 ? $filter[0][$returnField] : null;

}

使用 array_column 函数，这可以轻松实现已解决并且非常通用。

$array = [
  ['id' => 18460, 'field_id' => 14, 'parent_id' => 165, 'custom_tab_field_id' => 17775, 'status' => 0, 'field_type' => 0],
  ['id' => 18460, 'field_id' => 2, 'parent_id' => 165, 'custom_tab_field_id' => 17776, 'status' => 0, 'field_type' => 2],
  ['id' => 18460, 'field_id' => 14, 'parent_id' => 165, 'custom_tab_field_id' => 17777, 'status' => 2, 'field_type' => 2],
];

$findKey = 'custom_tab_field_id';
$getKey = 'status';
$findVal = 17777;

$arrKeyValue = array_column($array,$getKey,$findKey);

$status = $arrKeyValue[$findVal];  //2

该解决方案不包含错误处理，仅展示原理。 $arrKeyValue 是一个数组，如何：

array (
  17775 => 0,
  17776 => 0,
  17777 => 2,
)

尝试自行https://3v4l.org/SnVM4