javascript - 前端代码如何写出带交互效果的八卦图?
黄舟
黄舟 2017-04-11 11:38:50
[JavaScript讨论组]

要用前端代码写这样的一个图形;
需要达到的交互效果是:

  1. 当鼠标移动到里面某个区域时,该扇形区域变成灰色块

  2. 并且对应的外圈,边框变成红色

黄舟
黄舟

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全部回复(11)
PHPz

单纯的DOM非常麻烦,你应该用SVG或者canvas

这是SVG的例子

http://jsbin.com/fedehodaku/e...

<svg width="500" height="500" viewBox="0 0 1000 1000" xmlns="http://www.w3.org/2000/svg" style="position: fixed; top: 0px; left: 0px; background-color: white;">
<style>
    path.area {
        fill-opacity: 0;
        fill: #CCCCCC;
    }
    path.area:hover {
        fill-opacity: 1;
    }
</style>
<g stroke="gray" stroke-dasharray="10 10" fill-opacity="0">
    <circle cx="500" cy="500" r="200"></circle>
    <circle cx="500" cy="500" r="300"></circle>
    <circle cx="500" cy="500" r="400"></circle>
    <circle cx="500" cy="500" r="500" stroke="#FF6666"></circle>
</g>
<g stroke="gray">
    <line x1="600" x2="1000" y1="500" y2="500"></line>
    <line x1="570.71" x2="853.55" y1="570.71" y2="853.55"></line>
    <line x1="500" x2="500.00" y1="600" y2="1000"></line>
    <line x1="429.28" x2="146.44" y1="570.71" y2="853.55"></line>
    <line x1="400" x2="0" y1="500" y2="500.00"></line>
    <line x1="429.28" x2="146.44" y1="429.28" y2="146.44"></line>
    <line x1="500" x2="499.99" y1="400" y2="0"></line>
    <line x1="570.71" x2="853.55" y1="429.28" y2="146.44"></line>
</g>
<circle cx="500" cy="500" r="100" fill="#FF6666" stroke-opacity="0"></circle>
<path d="M600 500 A100 100 0 0 1 570.71 570.71 L641.42 641.42 A200 200 0 0 0 700 500 Z" class="area"></path>
<path d="M570.71 570.71 A100 100 0 0 1 500 600 L500 700 A200 200 0 0 0 641.42 641.42 Z" class="area"></path>
<path d="M500 600 A100 100 0 0 1 429.28 570.71 L358.57 641.42 A200 200 0 0 0 500 700 Z" class="area"></path>
<path d="M429.28 570.71 A100 100 0 0 1 400 500 L300 500 A200 200 0 0 0 358.57 641.42 Z" class="area"></path>
<path d="M400 500 A100 100 0 0 1 429.28 429.28 L358.57 358.57 A200 200 0 0 0 300 500 Z" class="area"></path>
<path d="M429.28 429.28 A100 100 0 0 1 500 400 L499.99 300 A200 200 0 0 0 358.57 358.57 Z" class="area"></path>
<path d="M500 400 A100 100 0 0 1 570.71 429.28 L641.42 358.57 A200 200 0 0 0 499.99 300 Z" class="area"></path>
<path d="M570.71 429.28 A100 100 0 0 1 600 500 L700 499.99 A200 200 0 0 0 641.42 358.57 Z" class="area"></path>
<path d="M700 500 A200 200 0 0 1 641.42 641.42 L712.13 712.13 A300 300 0 0 0 800 500 Z" class="area"></path>
<path d="M641.42 641.42 A200 200 0 0 1 500 700 L500 800 A300 300 0 0 0 712.13 712.13 Z" class="area"></path>
<path d="M500 700 A200 200 0 0 1 358.57 641.42 L287.86 712.13 A300 300 0 0 0 500 800 Z" class="area"></path>
<path d="M358.57 641.42 A200 200 0 0 1 300 500 L200 500.00 A300 300 0 0 0 287.86 712.13 Z" class="area"></path>
<path d="M300 500 A200 200 0 0 1 358.57 358.57 L287.86 287.86 A300 300 0 0 0 200 500.00 Z" class="area"></path>
<path d="M358.57 358.57 A200 200 0 0 1 499.99 300 L499.99 200 A300 300 0 0 0 287.86 287.86 Z" class="area"></path>
<path d="M499.99 300 A200 200 0 0 1 641.42 358.57 L712.13 287.86 A300 300 0 0 0 499.99 200 Z" class="area"></path>
<path d="M641.42 358.57 A200 200 0 0 1 700 499.99 L800 499.99 A300 300 0 0 0 712.13 287.86 Z" class="area"></path>
<path d="M800 500 A300 300 0 0 1 712.13 712.13 L782.84 782.84 A400 400 0 0 0 900 500 Z" class="area"></path>
<path d="M712.13 712.13 A300 300 0 0 1 500 800 L500 900 A400 400 0 0 0 782.84 782.84 Z" class="area"></path>
<path d="M500 800 A300 300 0 0 1 287.86 712.13 L217.15 782.84 A400 400 0 0 0 500 900 Z" class="area"></path>
<path d="M287.86 712.13 A300 300 0 0 1 200 500.00 L100 500.00 A400 400 0 0 0 217.15 782.84 Z" class="area"></path>
<path d="M200 500.00 A300 300 0 0 1 287.86 287.86 L217.15 217.15 A400 400 0 0 0 100 500.00 Z" class="area"></path>
<path d="M287.86 287.86 A300 300 0 0 1 499.99 200 L499.99 100 A400 400 0 0 0 217.15 217.15 Z" class="area"></path>
<path d="M499.99 200 A300 300 0 0 1 712.13 287.86 L782.84 217.15 A400 400 0 0 0 499.99 100 Z" class="area"></path>
<path d="M712.13 287.86 A300 300 0 0 1 800 499.99 L900 499.99 A400 400 0 0 0 782.84 217.15 Z" class="area"></path>
<path d="M900 500 A400 400 0 0 1 782.84 782.84 L853.55 853.55 A500 500 0 0 0 1000 500 Z" class="area"></path>
<path d="M782.84 782.84 A400 400 0 0 1 500 900 L500.00 1000 A500 500 0 0 0 853.55 853.55 Z" class="area"></path>
<path d="M500 900 A400 400 0 0 1 217.15 782.84 L146.44 853.55 A500 500 0 0 0 500.00 1000 Z" class="area"></path>
<path d="M217.15 782.84 A400 400 0 0 1 100 500.00 L0 500.00 A500 500 0 0 0 146.44 853.55 Z" class="area"></path>
<path d="M100 500.00 A400 400 0 0 1 217.15 217.15 L146.44 146.44 A500 500 0 0 0 0 500.00 Z" class="area"></path>
<path d="M217.15 217.15 A400 400 0 0 1 499.99 100 L499.99 0 A500 500 0 0 0 146.44 146.44 Z" class="area"></path>
<path d="M499.99 100 A400 400 0 0 1 782.84 217.15 L853.55 146.44 A500 500 0 0 0 499.99 0 Z" class="area"></path>
<path d="M782.84 217.15 A400 400 0 0 1 900 499.99 L1000 499.99 A500 500 0 0 0 853.55 146.44 Z" class="area"></path>
</svg>
伊谢尔伦

你可以自己写个代码,然后哪里出错,不通了来求助,你这样直接把需求粘贴出来,你来找免费劳动力了??兄弟我感觉不会有人给你回答的

高洛峰

想到一种 思路 四个 方块 盒子 ,

这四个 盒子 做为 父级盒子, 注意overflow : hidden , 每一个盒子 内 有 两个 用border-radius 处理的 1 / 4 圆

将 1/ 4 旋转一下,每个1/4圆 都被 方形 父盒子 遮住一半。

就可以实现了 ,

另外如果感觉 麻烦 的话, 就用CANVAS 慢慢画吧

天蓬老师
!function () {

  class Panel {
    constructor(canvas, x, y, r, n) {
      this.canvas = canvas;
      this.ctx = canvas.getContext('2d');
      this.ratio = 1;
      this.initScreenRatio();
      this.x = x * this.ratio;
      this.y = y * this.ratio;
      this.r = r * this.ratio;
      this.n = n * this.ratio;
      this.dr = Math.round(this.r / this.n);
      this.basePos = this.canvas.getBoundingClientRect();
      this.prePos = null;
      this.drawPanel();
      this.initEvent();
    }

    initScreenRatio() {
      const devicePixelRatio = window.devicePixelRatio || 1;
      const backingStoreRatio = this.ctx.webkitBackingStorePixelRatio ||
        this.ctx.mozBackingStorePixelRatio ||
        this.ctx.msBackingStorePixelRatio ||
        this.ctx.oBackingStorePixelRatio ||
        this.ctx.backingStorePixelRatio || 1;

      const ratio = devicePixelRatio / backingStoreRatio;
      this.canvas.style.borderWidth = 0;
      this.canvas.style.width = this.canvas.offsetWidth;
      this.canvas.style.height = this.canvas.offsetHeight;
      this.canvas.width = ratio * this.canvas.offsetWidth;
      this.canvas.height = ratio * this.canvas.offsetHeight;
      this.ratio = ratio;
    }


    drawPanel(clear) {
      const {x, y, ctx, r, dr, n,actived} = this;
      const _2PI = 2 * Math.PI;
      let i = 1;
      if(clear!==false){
        this.clear();
      }
      ctx.save();
      ctx.strokeStyle = '#ddd';
      ctx.setLineDash([8, 4]);

      //圆盘
      ctx.save();
      for (; i < n + 1; i++) {
        ctx.beginPath();
        ctx.arc(x, y, i * dr, 0, _2PI);
        if(i===n){
          ctx.strokeStyle = actived?'#f00':'#ddd';
        }
        ctx.stroke();
      }
      ctx.restore();
      //分割线
      ctx.translate(x, y);
      ctx.setLineDash([]);
      for (i = 0; i < 8; i++) {
        ctx.beginPath();
        ctx.moveTo(0, 0);
        ctx.lineTo(0, r);
        ctx.stroke();
        ctx.rotate(_2PI / 8);
      }
      ctx.restore();
    }

    clear(){
      this.ctx.clearRect(0,0,this.canvas.width,this.canvas.height);
    }

    getArea(px, py) {
      const {basePos, x, y, dr} = this;
      const dx = (px - basePos.left) * this.ratio - x;
      const dy = (py - basePos.top) * this.ratio - y;
      const d = Math.ceil(Math.sqrt(Math.pow(dx, 2) + Math.pow(dy, 2)));
      let anum = Math.ceil(d / dr);
      if (dx === 0) {
        anum = 0;
      }
      const actan = dx > 0 ? (dy > 0 ? Math.atan(dy / dx) : 2 * Math.PI + Math.atan(dy / dx)) : Math.PI + Math.atan(dy / dx);
      return {
        n: anum > this.n ? null : anum,
        rotate: Math.floor(actan * 4 / Math.PI)
      }
    }

    fillCellPath(pos, col) {
      const {ctx, dr, x, y} = this;
      if (pos.n) {
        this.clear();
        ctx.save();
        ctx.translate(x, y);
        ctx.rotate(pos.rotate * Math.PI / 4);
        ctx.beginPath();
        ctx.moveTo(0, 0);
        ctx.arc(0, 0, (pos.n) * dr, 0, Math.PI / 4);
        ctx.closePath();
        ctx.fillStyle = col || '#000';
        ctx.fill();
        ctx.beginPath();
        ctx.moveTo(0, 0);
        ctx.arc(0, 0, (pos.n - 1) * dr, 0, Math.PI / 4);
        ctx.closePath();
        ctx.fillStyle = '#fff';
        ctx.fill();
        ctx.restore();
        this.drawPanel(false);
      }
    }

    initEvent() {
      this.canvas.addEventListener('mousemove', (e) => {
        const pos = this.getArea(e.pageX, e.pageY);
        if (!this.prePos || this.prePos.n !== pos.n || this.prePos.rotate !== pos.rotate && pos.n) {
          this.actived = true;
          if (this.prePos) {
            this.fillCellPath(this.prePos, '#fff');
          }
          this.fillCellPath(pos, '#000');
          this.prePos = pos;
        }else if(!pos.n){
          this.actived = false;
          this.drawPanel();
        }
      })
    }

  }


  const canvas = document.getElementById('canvas');
  const panel = new Panel(canvas, 300, 300, 250, 5);

} ()
大家讲道理

给你个提示:用border-radius做

天蓬老师

用角度和距离圆心距离确定鼠标位置,就是那个灰色的块用canvas画出来。

阿神

dom不用考虑,即使能实现,兼容性什么的也很难保证,这种复杂不规则图形用canvas或SVG把

高洛峰

实现第一点的话,一个字,(算法)

巴扎黑

这又是楼主的大学期末作业把

天蓬老师

其实这种图用D3写也不麻烦、基于svg

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