比如有四个列表，布局几乎一样，只有细微的区别，Controller的代码自然也就非常类似了，比如只有请求参数不同。

initialize();

        $scope.refreshHub[$scope.REFRESH_METHOD[$scope.nowIndex]] = function () {
            $scope.model_request.pageNum = 1;
            business_XW1.requestNewsList($scope.model_request).then(
                function (okRs) {
                    $scope.list = okRs.response.parram;
                    setTimeout(function () {
                        $rootScope.loadMoreState = $scope.list.length >= $scope.model_request.pageSize;
                    },500);
                },$scope.errorCallback
            ).always(function () {
                $rootScope.$broadcast('scroll.refreshComplete');
            });
        };
        $scope.loadHub[$scope.LOAD_METHOD[$scope.nowIndex]] = function () {
            $scope.model_request.pageNum++;
            business_XW1.requestNewsList($scope.model_request).then(
                function (okRs) {
                    Array.prototype.push.apply($scope.list,okRs.response.parram);
                    $rootScope.loadMoreState = okRs.response.total > $scope.list.length;
                },$scope.errorCallback
            ).always(function () {
                $rootScope.$broadcast('scroll.infiniteScrollComplete');
            });
        };

        // helper methods ~
        function initialize() {
            $scope.model_request = new xw_model.Corporation();
            $scope.list = [];
        }

比如这段代码，这四个列表的Controller中，只有model_request参数不同，那么我该如何才能复用这段代码呢？