Java高效处理ZIP文件：避免内存溢出，选择正确的读写方式

import java.io.*;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;

public class ZipFileProcessor {

    public static void extractZipFile(String zipFilePath, String destDir) throws IOException {
        File destDirectory = new File(destDir);
        if (!destDirectory.exists()) {
            destDirectory.mkdirs();
        }

        try (ZipInputStream zipIn = new ZipInputStream(new FileInputStream(zipFilePath))) {
            ZipEntry entry = zipIn.getNextEntry();
            while (entry != null) {
                String filePath = destDir + File.separator + entry.getName();
                if (!entry.isDirectory()) {
                    // 如果是文件，则解压
                    extractFile(zipIn, filePath);
                } else {
                    // 如果是目录，则创建目录
                    File dir = new File(filePath);
                    dir.mkdirs();
                }
                zipIn.closeEntry();
                entry = zipIn.getNextEntry();
            }
        }
    }

    private static void extractFile(ZipInputStream zipIn, String filePath) throws IOException {
        try (BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(filePath))) {
            zipIn.transferTo(bos);
        }
    }

    public static void main(String[] args) {
        String zipFilePath = "path/to/your/archive.zip"; // 替换为你的ZIP文件路径
        String destDir = "path/to/destination/directory"; // 替换为你的解压目录
        try {
            extractZipFile(zipFilePath, destDir);
            System.out.println("ZIP file extracted successfully!");
        } catch (IOException e) {
            System.err.println("Error extracting ZIP file: " + e.getMessage());
            e.printStackTrace();
        }
    }
}