java调用python脚本怎么传参？

public class PythonCaller {
    public static void main(String[] args) {
        String pythonScript = "path/to/your/script.py";
        String param1 = "hello";
        String param2 = "world";

        ProcessBuilder pb = new ProcessBuilder(
            "python", pythonScript, param1, param2
        );

        try {
            Process process = pb.start();

            // 读取Python脚本的输出（可选）
            java.io.BufferedReader reader = new java.io.BufferedReader(
                new java.io.InputStreamReader(process.getInputStream())
            );
            String line;
            while ((line = reader.readLine()) != null) {
                System.out.println(line);
            }

            // 等待脚本执行完成
            int exitCode = process.waitFor();
            System.out.println("Exit code: " + exitCode);

        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

import sys

if __name__ == "__main__":
    # argv[0] 是脚本名，argv[1] 开始是传入的参数
    if len(sys.argv) > 1:
        arg1 = sys.argv[1]
        arg2 = sys.argv[2]
        print(f"Received: {arg1}, {arg2}")
    else:
        print("No arguments provided.")

String line;
while ((line = reader.readLine()) != null) {
    System.out.println("Output: " + line);
}

基本上就这些。只要把参数追加在命令后面，Python脚本用<code>sys.argv</code>接收，就能实现传参。关键是处理好路径、异常和输出读取。